- #1
KLscilevothma
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To draw all possible structures for C4H8O, the first step we need to do is to calculate the degree of unsaturation of the molecule.
Degree of Unsatuation of C4H8O = (C+O-H)/2 = (2*4+2-8*1)/2 = 1 (meaning it has 1 double bond)
[degree of C=2, H=1 and O=2]
My question is why can the degree of unsatuation be caculated by the above formula, which only works for compounds with double bond(s) or satuated compounds. Also why is the degree of Carbon assigned to be 2, H=1 and O=2 ?
Degree of Unsatuation of C4H8O = (C+O-H)/2 = (2*4+2-8*1)/2 = 1 (meaning it has 1 double bond)
[degree of C=2, H=1 and O=2]
My question is why can the degree of unsatuation be caculated by the above formula, which only works for compounds with double bond(s) or satuated compounds. Also why is the degree of Carbon assigned to be 2, H=1 and O=2 ?