Isomorphism between II18 / <3> and II3

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Homework Statement


Show that II18 / <3> is isomorphic to II3.


Homework Equations


II18 = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}
<3> = {0,3,6,9,12,15}
II3 = {1,2,3}
II18 / <3> = {3,6,9,12,15,18}

The Attempt at a Solution

 
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aliciaislol said:

Homework Statement


Show that II18 / <3> is isomorphic to II3.


Homework Equations


II18 = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}
<3> = {0,3,6,9,12,15}
II3 = {1,2,3}
II18 / <3> = {3,6,9,12,15,18}

The Attempt at a Solution

Looks to me like your proof says they are NOT isomorphic! If they don't have the same number of members, they certainly aren't isomorphic.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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