Isosceles triangle with angle bisector

[Frank212]

Homework Statement

Find x[/B]

Homework Equations

a+b+c=180[/B]

The Attempt at a Solution

ADB= 65+65+50=180
How do I find x in DBC?

 

[SammyS]

Homework Statement

Find x[/B]
View attachment 104594

Homework Equations

a+b+c=180[/B]

The Attempt at a Solution

ADB= 65+65+50=180
How do I find x in DBC?

What is the measure of angle CBD ?

 

[Frank212]

What is the measure of angle CBD ?

What is the measure of angle CBD ?

ADB=50+65+65=180
angle bisector -> angle on a line 180 degrees. 180-65=115
x= 180-115=65, 65/2=32.5
CBD=32.5+115+32.5

x=32.5

 

[SammyS]

ADB=50+65+65=180
angle bisector -> angle on a line 180 degrees. 180-65=115
x= 180-115=65, 65/2=32.5
CBD=32.5+115+32.5

x=32.5

Actually, I asked about angle CBD, ( ∠ CBD ), not triangle CBD ( Δ CBD ).

Maybe, that's what you mean by

" angle bisector -> angle on a line 180 degrees. 180-65=115 ",​

but an angle bisector cuts an angle exactly into two angle of equal measure.

So, yes, .∠ CBD = 180° - 65° = 115° .

It's really very confusing, and incorrect, when you state the following.

CBD=32.5+115+32.5