- #1

- 43

- 3

I'm trying to understand how to use the fact that the total isospin is conserved in all strong processes in the particular case (

*vide*Griffiths, pages 118 and 119):

$$ p+p \rightarrow d+\pi^+ $$

Griffiths first argues that the deuteron d has isospin I=0, because of experimental reasons, basically. He uses this to conclude that "the isospin states on the right are |11>, |10>,

and |11>, respectively, whereas those on the left are I1 1>, $$\frac{1}{\sqrt{2}}(|10>+|00>)$$

and |1 - 1>"

I do not understand how he concludes this. Could you please enlighten me?