Isotropic Harmonic Oscillator Orbit Calculation | Central Motion Problem

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Homework Statement



Consider an isotropic harmonic oscillator whose potential is given by V(r)=0.5kr^2. Calculate the value of r(t) for the orbit of a particle.


Homework Equations



dr/dt=\sqrt{2/m(E-0.5kr^2-L^2/2mr^2)} (call the right side of the eqn 'stuff')



The Attempt at a Solution



I'm unable to solve the integral \int\frac{dr}{stuff} as is.
I'm sure there's a subsitution or some other trick I can do to make the integral solvable but I can't figure it out =/
 
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Note that when you separate the equation, you'll get a fraction within a fraction:
\frac{\mathrm{d}r}{\sqrt{\cdots + A/r^2}} = \cdots
It's usually a good idea to simplify such expressions like so:
\frac{\mathrm{d}r}{\sqrt{\frac{1}{r^2}(\cdots + A)}} = \cdots
so that you're left with a regular polynomial times some overall factor. With a couple more steps, you can get that into a form where you can use the substitution u = r^2.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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