Joining two wires, magnetic fields and a little algebra

AI Thread Summary
To find the magnetic field strength on the line joining two wires with currents flowing, the equation B = μ iD / π(D² − d²) can be derived. This involves summing the contributions of the magnetic fields from both wires at a point a distance d from the midpoint O. A relevant trigonometric identity, (D² − d²) = (D + d)(D - d), is useful in simplifying the calculations. The standard formula for the magnetic field due to a long straight wire, B = μ i / 2π d, serves as a foundational reference. The discussion highlights the need for clarity in applying these concepts to solve the problem effectively.
shyguy79
Messages
99
Reaction score
0

Homework Statement


Consider a general point on the line joining the two wires and a distance d
away from the mid-point O. By summing the magnetic field due to currents of magnitude i flowing in both the wires which are non-zero, show that on the line joining the two wires, the magnetic field strength is given by:

B= μ iD / π(D2 −d2)

Homework Equations


(D^2 −d^2) = (D+d)(D-d) ****** a simple trig identity
B= μ i / 2π d

The Attempt at a Solution


I'm kinda stuck - any pointers on where to start?
 
Physics news on Phys.org
Just bumping it back up - anyone any ideas?
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

The distance where the magnetic field of two wires is zero
Replies
2
Views
4K
Magnetic field due to electric wire
Replies
6
Views
1K
Magnetic field pointing into a normal magnetized compass needle
Replies
16
Views
1K
Why is magnetic field B along a straight wire circular not radial?
Replies
14
Views
3K
Electromagnetism question -- Forces between two current carrying wires
Replies
7
Views
2K
Magnetic field due to a straight wire and circular arc
Replies
20
Views
3K
Magnetic field at origin due to infinite wires and semicircular turn
Replies
3
Views
2K
Where Will Earth's Magnetic Field Cancel a Wire's B-Field?
Replies
5
Views
2K
Does a Bent Wire Affect Induction Calculations?
Replies
7
Views
2K
Magnetic field created by a wire
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top