Joint Probability Density Function

twoski
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Homework Statement



The joint probability density function of X and Y is given by
f(x, y) = c( x3 + xy/4 )

0 < x < 1
0 < y < 2

(a) For what value of c is this a joint density function?
(b) Using this value of c, compute the density function of Y .
(c) Using this value of c, nd PfX > Y g.

The Attempt at a Solution



I'm looking through my notes and i can't find anything that helps me solve A... :(
 
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The double integral, over the region, of the density function must be 1.
 
So the idea is, if i do a double integral on this function i should end up with c * some value, and i need to find a value for c such that c * some value = 1?
 
twoski said:
So the idea is, if i do a double integral on this function i should end up with c * some value, and i need to find a value for c such that c * some value = 1?

Try it yourself to see!
 
So i did it and i ended up with 3/4 * c... So the idea now is that i want C to equal 1?

And how would i start computing the density function of Y?
 
Last edited:
twoski said:
So i did it and i ended up with 3/4 * c... So the idea now is that i want C to equal 1?

And how would i start computing the density function of Y?

Do you not understand that you want the double integral = 1? That means that you need to equate your result to 1.

As to the density of Y: it will just be the *marginal* density of Y. The meaning of this was already dealt with in another thread.
 
Okay I've managed to figure out everything except for the last question. I have formulas for P( X ≤ x ) but it's asking me to find P( X < Y ).
 
twoski said:
Okay I've managed to figure out everything except for the last question. I have formulas for P( X ≤ x ) but it's asking me to find P( X < Y ).

Draw a picture of that region inside your given domain and integrate the joint density over it.
 
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