Child's Displacement on Cubical Jungle Gym: Solving the Problem

[c4iscool]

I am having problems figuring this out. How should I go about this?


A child starts at one corner of a cubical jungle gym in a playground and climbs up to the diagonally opposite corner. The original corner is the coordinate origin, and the x-, y- and z-axes are oriented along the jungle gym edges. The length of each side is 2m. The child's displacement is?

 

[tjr39]

Break it down into two smaller and easier problems. And draw yourself a diagram! Solve using Pythagoras a² + b² = c²

 

[Moetasim]

To solve this problem, we can use the Pythagorean theorem to calculate the child's displacement. First, we need to determine the distance the child climbs along each axis. From the origin to the opposite corner, the child climbs 2m along the x-axis, 2m along the y-axis, and 2m along the z-axis. This forms a right triangle with sides of length 2m, 2m, and 2m√2. Using the Pythagorean theorem, we can calculate the displacement as the hypotenuse of this triangle, which is approximately 2.83m. Therefore, the child's displacement on the cubical jungle gym is 2.83m.