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DB

501
0
what pressure will be exerted by 0.450 mol of a gas at 25 degrees Celsius if it is contained in a vessel wwhose volume is 0.65 L?

[tex]\frac{P_1 * 0.65 L}{298 K * 0.450 mol}=8.31_\frac{L*kPa}{K*mol}
[/tex]

[tex]P_1 \sim 1714.4 kPa[/tex]

is this right?
thanks
 

Pengwuino

Gold Member
4,764
10
Yes that is correct although you didn't setup the equation as best you could.

[tex]\frac{{PV}}
{{RT}} = n[/tex]

could have been changed to

[tex]\frac{{nRT}}
{V} = P[/tex]

to make it a much simpler calculation since you are actually looking for P
 

DB

501
0
thanks pengwuino, ya i know, the simple algebra doesn't bother me tho :)
 

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