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what pressure will be exerted by 0.450 mol of a gas at 25 degrees Celsius if it is contained in a vessel wwhose volume is 0.65 L?
[tex]\frac{P_1 * 0.65 L}{298 K * 0.450 mol}=8.31_\frac{L*kPa}{K*mol}
[/tex]
[tex]P_1 \sim 1714.4 kPa[/tex]
is this right?
thanks
[tex]\frac{P_1 * 0.65 L}{298 K * 0.450 mol}=8.31_\frac{L*kPa}{K*mol}
[/tex]
[tex]P_1 \sim 1714.4 kPa[/tex]
is this right?
thanks