# Just checking

#### DB

what pressure will be exerted by 0.450 mol of a gas at 25 degrees Celsius if it is contained in a vessel wwhose volume is 0.65 L?

$$\frac{P_1 * 0.65 L}{298 K * 0.450 mol}=8.31_\frac{L*kPa}{K*mol}$$

$$P_1 \sim 1714.4 kPa$$

is this right?
thanks

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#### Pengwuino

Gold Member
Yes that is correct although you didn't setup the equation as best you could.

$$\frac{{PV}} {{RT}} = n$$

could have been changed to

$$\frac{{nRT}} {V} = P$$

to make it a much simpler calculation since you are actually looking for P

#### DB

thanks pengwuino, ya i know, the simple algebra doesn't bother me tho :)

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