Kepler's Third Law and centripetal acceleration

Shackleford
Messages
1,649
Reaction score
2
I'm not getting very far with these problems. Don't know what my problem is.

Given a circular orbit, the centripetal acceleration is given by the gravitational force between the two stars. I chose the center to be halfway between the stars d/2.

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-13225621.jpg?t=1284437088

http://i111.photobucket.com/albums/n149/camarolt4z28/2010-09-13225642.jpg?t=1284437089
 
Last edited by a moderator:
Physics news on Phys.org
Try writing v in terms of d and τ.
 
vela said:
Try writing v in terms of d and τ.

pi*d = vt

(1/t)*pi*d = v

v = pi*d*τ

That doesn't get me anywhere.
 
Last edited:
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top