Kibble problem (linear motion chap. 2)

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Homework Help Overview

The problem involves a particle of mass m moving under a force defined by F = -kx + c/x, where k and c are positive constants. Participants are tasked with finding the potential energy function, determining the position of equilibrium, and calculating the frequency of small oscillations about that equilibrium.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the meaning of equilibrium, with some suggesting that the total force must be zero at that point. There are attempts to derive relationships between constants and equilibrium position, as well as questions about the potential energy function.

Discussion Status

The discussion has seen various interpretations of equilibrium and potential energy. Some participants have provided feedback on the correctness of others' reasoning, while others express uncertainty about their understanding and the implications for their exam performance. There is a mix of attempts to clarify concepts and explore the problem further.

Contextual Notes

Participants mention that the problem is part of an exam question and that similar questions were assigned as homework. There is a sense of urgency and concern regarding the implications of solving the problem correctly for their exam marks.

levilevi
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Homework Statement



7. A particle of mass m moves (in the region x > 0) under a force F =
−kx+c/x, where k and c are positive constants. Find the corresponding
potential energy function. Determine the position of equilibrium, and
the frequency of small oscillations about it.



Homework Equations



dx/dt = [(2/m)(E - V(x)]^1/2

The Attempt at a Solution


dx/[(2/m)(E+ Clnx - (1/2)kx^2]^1/2 = dt
V = -Clnx + (1/2)kx^2]^1/2
i think at equilibrum point V(x) must be zero but then how can i continue? This is en exam question and i must solve it completely correct. Thank you for your answers. (my firt language is not english. Sorry for mistakes.)
 
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levilevi said:
i think at equilibrum point V(x) must be zero but then how can i continue?
V(x) is not zero at equilibrium. What does equilibrium mean to you?
 
Thanks, you are right. Total force, i think is zero at equilibrium point. So;
-ka + [tex]\frac{c}{a}[/tex] = 0 (a = equilibrium point.) k = c/a2
Is it true?
 
levilevi said:
Thanks, you are right. Total force, i think is zero at equilibrium point. So;
-ka + [tex]\frac{c}{a}[/tex] = 0 (a = equilibrium point.) k = c/a2
Is it true?
It is true. If this is an exam question, you have to finish it by yourself. I will not tell you how to solve it, but I can tell you if something is correct or not and the rest is up to you.
 
The exam was three days ago. Nobody could solve this question and a similar one (in which F = -kx +a/x^3) The teacher gave us as a homework. If i will solve maybe my exam mark will increase but i am not sure this. Maybe not. If you don not want to help it is up to you. I will study on it again and again...
 
Last edited:
I solved at last. a=(c/k)^1/2 and w=(2k/m)^1/2 , w=(V''(a) /m)^1/2. Thanks.
 

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