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Kinematcis, archer and his arrow

  1. Aug 16, 2012 #1
    An archer shoots an arrow straight up into the air with an initial velocity of 45 m/s . Calculate the maximum height of the arrow.

    The equation I would use for this is:
    Vf^2 = Vo^2+2as

    where:
    Vf is final velocity
    Vo is initial velocity
    a is acceleration (gravity)
    s is displacement

    plug in the numbers we know:
    0^2 = 45^2 + 2(-9.8)s

    now solve for s

    0=2025-19.6s
    -2025=-19.6s

    s = 103.32 meters.


    is this right
     
  2. jcsd
  3. Aug 16, 2012 #2

    CAF123

    User Avatar
    Gold Member

    Yes.
    I would say it is best to rearrange the equation to make [itex] s [/itex] the subject first and then substitute numbers.
     
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