- #1
alicia113
- 103
- 0
An archer shoots an arrow straight up into the air with an initial velocity of 45 m/s . Calculate the maximum height of the arrow.
The equation I would use for this is:
Vf^2 = Vo^2+2as
where:
Vf is final velocity
Vo is initial velocity
a is acceleration (gravity)
s is displacement
plug in the numbers we know:
0^2 = 45^2 + 2(-9.8)s
now solve for s
0=2025-19.6s
-2025=-19.6s
s = 103.32 meters.is this right
The equation I would use for this is:
Vf^2 = Vo^2+2as
where:
Vf is final velocity
Vo is initial velocity
a is acceleration (gravity)
s is displacement
plug in the numbers we know:
0^2 = 45^2 + 2(-9.8)s
now solve for s
0=2025-19.6s
-2025=-19.6s
s = 103.32 meters.is this right