Kinematic Equations Homework Solutions

AI Thread Summary
The discussion focuses on solving kinematic equations related to displacement, velocity, and acceleration. It details calculations for specific problems, including average velocity, acceleration, and total distance traveled. The importance of using SUVAT equations for accurate results is emphasized, noting that while the initial answers are generally correct, they could be refined for precision. Participants discuss the significance of significant figures in reporting results and the potential for improved accuracy through optimal equation selection. Overall, the conversation highlights the application of kinematic principles in problem-solving.
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Homework Statement


upload_2016-3-21_23-25-15.png


Homework Equations


relevant equations are listed with each question

The Attempt at a Solution



25. **

Displacement = 131 km (South)

Average velocity = total displacement / total time

Average velocity = 131 km (S) / 2.0 h

Average velocity = 65.5 km /h (south)


26. **

Given information:

v1 = 75 km/h

Convert to m/s:

(75 km/h) x (1000 m/1 km) x (1 h/3600 s) = 20.8 m/s

d = 42 m

total time = 3.4 s

a)

Calculate acceleration:

a = v2 – v1 / total time

a = 0 – 20.8 m/s / 3.4 s

a = -6.12 m/s2

Calculate distance:

total distance= v1(total time) + ½ a (total time)^2

= (20.8 m/s) x (3.4 s) – ½ (6.12 m/s2) x (3.4 s)2

= 35.35 m

Andrew traveled 35.35 m before stopping.b) ***

Andrew did not hit the fox.

42 m – 35.35 m = 6.65 m
c) ***

35.35 m / 4.2 m = 8.4 m

It took approx. 8 van lengths for Andrew to stop.


27. **

Given information:

v1 = 2.1 m/s (up)

total time = 3.0 s

acceleration = -9.81 m/s2 (down)

a)

Equation:

total displacement = v1(total time) + ½ a (total time)^2

Substitute and solve:

d = (2.1 m/s) x (3.0 s) – ½ (9.8 m/s2) x (3.0 s)^2

d = -37.8 = 37.8 m

Marian’s Balcony is 37.8 m high.

b)

v2^2 = v1^2 + 2a(total displacement)

= (2.1 m/s)2 + 2(-9.8 m/s2) x (-37.8 m)

= √746

= 27.3 m/s (down)

 

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That's all about right, but you could have used a shorter and more accurate path in 27 a) and b).
In a) do you know a SUVAT equation relating acceleration, time, initial speed and distance?
In b) do you know a SUVAT equatiom relating initial speed, final speed, time and acceleration?
(Using an intermediate result, as from 27a), as input to a further result often leads to loss of precision. E.g. while it might be appropriate to quote an intemediate result to 3 digits, you should use at least four as input to the next step.)
 
can you explain what SUVAT equations are?
 
so for questions 25, and 26 are they completely correct?
and when you say 'shorter and more accurate path to solve 27 a) and b)' do u mean that the answers are not as accurate as they should be? did i do it right or wrong?
 
alexandria said:
so for questions 25, and 26 are they completely correct?
and when you say 'shorter and more accurate path to solve 27 a) and b)' do u mean that the answers are not as accurate as they should be? did i do it right or wrong?
They could be a bit more accurate. 27b is out by about 1 percent, whereas quoting three significant figures here implies about 0.3% or better.
It's not a question of right or wrong. Using the best choice of equations from the SUVAT collection would have involved less working and produced more accurate answers.
 
i see,
what about 25 and 26, i feel like I am missing something
 
alexandria said:
i see,
what about 25 and 26, i feel like I am missing something
Why? They look fine to me.
 
ok thanks just clarifying :smile:
 

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