Kinematic Equations: Vector & Scalar Formulas

AI Thread Summary
The discussion focuses on the kinematic equations for motion with constant acceleration, emphasizing their vector and scalar forms. The three primary vector equations are presented, which can be expanded into scalar equations for each spatial component. A specific scalar equation, (v_f)^2 = (v_0)^2 + 2a(x_f - x_0), is discussed, with participants exploring its derivation from vector equations. The conversation also touches on the use of the vector dot product to combine these equations into a single expression. The thread concludes with a query about the missing variable in the derived equation.
fog37
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Hello Forum,
the kinematic equations for motion with constant acceleration are vector equations which can each be expanded into 3 scalar (or component equations). The vector equations are:

v_f = v_0 + a (Delta_t)

r_f
= r_0 + v_0 (Delta_t) + (0.5) a (Delta_t)^2

r_f
= r_0 + (0.5) (v_f + v_0) (Delta_t)

From these three vector equation we can write the corresponding scalar equations for the x,y and z components.

What about the scalar equation (v_f)^2 = (v_0)^2 +2a (x_f -x_0) ? It can be written for each scalar component.
What is the corresponding vector equation for it from which it comes from?

thanks
fog37
 
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fog37 said:
It can be written for each scalar component.
That is, $$v_{xf}^2 = v_{x0}^2 + 2a_x (x_f - x_0) \\ v_{yf}^2 = v_{y0}^2 + 2a_y (y_f - y_0) \\ v_{zf}^2 = v_{z0}^2 + 2a_z (z_f - z_0)$$ Add the three equations together. Are you familiar with the vector dot product?
 
Thanks! I see how the addition of the three gives a single equation with dot products:

[ v_f dot v_f ] = [ v_0 dot v_0 ]+ 2 [a dot (r_f - r_0) ]

correct? Where does this equation come from? I guess it derives from that single differential equation dv/dt = a ...
 
I think you can get it by combining two of the equations in your first post. Note which variable is "missing" from this equation.
 
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