Kinematic Problem: How Long to Reach Half Speed in a Fluid?

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The discussion focuses on a kinematic problem involving a marble's acceleration in a fluid, where the acceleration is proportional to the square of its speed, given by the equation a = -3.00V^2. The marble enters the fluid at a speed of 1.50 m/s, and the goal is to determine how long it takes to reach half that speed. Initial attempts to solve the problem using standard kinematic equations led to confusion, but the solution involves applying calculus and separation of variables. The user realizes that integrating the equation dv/dt = -3v^2 is the correct approach to find the time taken to reach half speed. The discussion highlights the importance of calculus in solving differential equations related to motion in fluids.
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Hi all, can some one please help me on this problem;

The acceleration of a marble in a certain fluid is proportional to the speed of the marbles, and is given (in SI units) by a= -3.00V^2 for v>0. If it enters this fluid with a speed of 1.50 m/s, how long will it take for the marble to reach half its intial speed.


I have released that

Vf=Vi + a(t)

.75=1.5+ a(t)
-.15=a(t)


and that A=(Vf-VI)/t

I am stuck after this. Please help me.
 
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Do you calculus??This problem involves solving a first ODE through separation of variables...

Daniel.
 
I am still stock on this problem. I have tryed using separation of variables but it just leads me in a circle.
 
\frac{dv}{dt} = -3 v^2
-\frac{1}{3 v^2} dv = dt
Integrate!
 
I can't beilve I did not see that :eek: LOL, its soo easy. Thank you for your help.
 
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