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Kinematics 12

  1. Jan 19, 2014 #1
    1. Problem
    a basketball player is standing 9.5m from the basket which is at a height of 3.1m. She throws the ball from an initial height of 2.0m at an angle of 35 degrees above horizontal. The ball goes straight through the basket. Find v initial

    2. Equations
    Any range / Kinematic equations

    3. My work
    I tried separating the problem into x and y components, then used
    -2 = Vi sin 35 + (1/2) * g * t^2
    and
    dx = Vi cos 35 * t

    But this kept giving me incorrect answers.
     
  2. jcsd
  3. Jan 19, 2014 #2
    Your equations are mostly correct, but you forget the ##t## variable next to ##v_i\sin(35^{\circ})##. That is because the ##y##-component distance formula is ##y(t) = y_0 + v_i\sin(\theta)t + \dfrac{1}{2}gt^2##. Be sure to first express in that form.
     
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