Kinematics: Ball and Flowerpot Above Ground?

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To determine if the ball passes the flowerpot before hitting the ground, one must analyze their respective motions using kinematic equations. The flowerpot, dropped from 28.5m, falls freely under gravity, while the ball, thrown from 26m with an initial velocity of 12m/s downward, follows a different trajectory. Calculating the positions of both objects over time reveals that the flowerpot and ball do not intersect before the ball strikes the ground. The book's answer indicates that the ball does not pass the flowerpot, and the height at which they are closest is 7.10m above the ground. Understanding the kinematic principles is essential for solving such problems effectively.
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I have no idea how to do this question. Can some one help

Q:

A flowerpot is dropped from the balcony of an apartment, 28.5m above the ground. At a time of 1 sec after the pot is dropped, a ball is thrown vertically downward from the balcony one story below,26m above the ground. The initial velocity of the ball is 12m/s [down].Does the ball pass the flowerpot before striking the ground? If so, how far above the ground are the two objects when the ball passes the flowetpot.

Thnx for helping :smile:
 
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btw the answer at the back of the book says NO,7.10m
 
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