Kinematics in 1D: Determining Velocity After 0.5s

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A stone is thrown upward with an initial velocity of +7.0 m/s and experiences a constant acceleration of -9.81 m/s². To determine the velocity after 0.5 seconds, the equation vf = vi + at can be applied. Substituting the values, vf = 7.0 m/s + (-9.81 m/s² * 0.5 s) results in a final velocity of approximately +1.5 m/s. The discussion emphasizes the importance of using the correct kinematic equation for one-dimensional motion. Understanding the direction of the throw is crucial for accurate calculations.
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1. A stone is thrown with an initial velocity of +7.0 m/s. The acceleration of the stone is a constant and has the value of -9.81m/s^2.What is the velocity of the stone after 0.5s?



2. Homework Equations
vf=vi+at?
i have no idea



3. The Attempt at a Solution
i can't find the right equation to put this in
 
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What direction is it thrown? Never mind--your title suggests 1D motion, so I presume straight up.

You have the correct equation. Use it!
 

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