What Is the Change in Velocity and Acceleration of a Rebounding Ball?

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The discussion revolves around calculating the change in velocity and acceleration of a ball rebounding off a wall. The initial velocity is 36 m/s westward, and after rebounding, it moves at 27 m/s eastward. The change in velocity (Δv) is calculated as the final velocity minus the initial velocity, resulting in -9 m/s when considering eastward as positive. To find acceleration, the change in velocity is divided by the time of impact, which lasts 0.14 seconds. The conversation emphasizes the importance of correctly interpreting vector directions and absolute values in these calculations.
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Homework Statement


A ball moving westward at 36 m/s hits a wall and rebounds at 27 m/s, eastward. (a) What is the change Δv in the vector velocity? (This is effectively the velocity of the rebounding ball relative to an image of it passing through the wall unaffected. It’s not the same as the 9 m/s reduction in the scalar speed!)

(b) Find the acceleration during the impact if that lasts 0.14 s.

2. The attempt at a solution

For change in velocity I had 9 m/s eastward. I don't know if that is correct.
 
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If we take positive direction as being Eastward then the ball's velocity prior to impact is -36 m/s (that's a minus sign there).

What is the velocity after impact?

What is the second one minus the first one?
 
so the velocity after impact is -9m/s.
would I use this to find the acceleration?
 
andrewkirk said:
If we take positive direction as being Eastward then the ball's velocity prior to impact is -36 m/s (that's a minus sign there).

What is the velocity after impact?

What is the second one minus the first one?
would I use that to find the acceleration?
 
Speeder63 said:
so the velocity after impact is -9m/s.
No.
The absolute value of the velocity has to equal the speed.
 
andrewkirk said:
No.
The absolute value of the velocity has to equal the speed.
So if the velocity is -9m/s the absolute velocity is 9m/s?
 
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