- #1
princessotes
- 2
- 0
Homework Statement
Humpty Dumpty had a great fall from a roof. It took him 2.25s to fall. How high was the roof?
Kinematics Problem: How High Was Humpty Dumpty's Fall?
- Thread starter princessotes
- Start date
AI Thread Summary
Humpty Dumpty fell from a roof in 2.25 seconds, prompting a discussion on calculating the height of the fall. The problem suggests that he experienced free fall, with initial velocity (u) at 0 and acceleration (a) equal to gravity (g). The relevant equation for height (H) is H = ut + 1/2at². Participants noted the importance of correctly inputting values into the calculator for accurate results. The conversation emphasizes the need for clarity in understanding the motion involved in the problem.
Humpty Dumpty had a great fall from a roof. It took him 2.25s to fall. How high was the roof?
- #2
ehild
Science Advisor
Homework Helper
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princessotes said:
The policy here is that you have to show your attempt at a solution. How does Humpty-Dumpty move? with constant velocity? Or does he accelerate?
- #3
harsh_sinha
- 11
- 2
It seems like a case of free-fall.
u=0,a=g and t is given
Use the equation H=ut+1/2at2
But this is what I presume.There isn't any clear information about the motion of Humpty Dumpty.
u=0,a=g and t is given
Use the equation H=ut+1/2at2
But this is what I presume.There isn't any clear information about the motion of Humpty Dumpty.
- #4
princessotes
- 2
- 0
Thanks, I got it.
I used H=ut+1/2at2
but it seemed I was inputting the wrong digit to the calculator
I used H=ut+1/2at2
but it seemed I was inputting the wrong digit to the calculator
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Here is what I tried
This question was actually asked in one of our engineering entrances.
The answer was 1D.
My teachers say that we have to use μₘ/fₘ to get to this answer. I cannot understand why. I'll be really glad if you could tell me the exact definition of power (numerically) that works in all scenarios.
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