- #1
princessotes
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Homework Statement
Humpty Dumpty had a great fall from a roof. It took him 2.25s to fall. How high was the roof?
Kinematics Problem: How High Was Humpty Dumpty's Fall?
- Thread starter princessotes
- Start date
AI Thread Summary
Humpty Dumpty fell from a roof in 2.25 seconds, prompting a discussion on calculating the height of the fall. The problem suggests that he experienced free fall, with initial velocity (u) at 0 and acceleration (a) equal to gravity (g). The relevant equation for height (H) is H = ut + 1/2at². Participants noted the importance of correctly inputting values into the calculator for accurate results. The conversation emphasizes the need for clarity in understanding the motion involved in the problem.
Humpty Dumpty had a great fall from a roof. It took him 2.25s to fall. How high was the roof?
- #2
ehild
Science Advisor
Homework Helper
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princessotes said:
The policy here is that you have to show your attempt at a solution. How does Humpty-Dumpty move? with constant velocity? Or does he accelerate?
- #3
harsh_sinha
- 11
- 2
It seems like a case of free-fall.
u=0,a=g and t is given
Use the equation H=ut+1/2at2
But this is what I presume.There isn't any clear information about the motion of Humpty Dumpty.
u=0,a=g and t is given
Use the equation H=ut+1/2at2
But this is what I presume.There isn't any clear information about the motion of Humpty Dumpty.
- #4
princessotes
- 2
- 0
Thanks, I got it.
I used H=ut+1/2at2
but it seemed I was inputting the wrong digit to the calculator
I used H=ut+1/2at2
but it seemed I was inputting the wrong digit to the calculator
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler:
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