A fireman, 28.7 m away from a burning building, directs a stream of water from a ground level fire hose at an angle of 49.5° above the horizontal. If the speed is 39.6 m/s, at what height will the stream of water hit the building?(adsbygoogle = window.adsbygoogle || []).push({});

Got this right on the first test, and can't figure it out again right now for some reason?!

Anyway, I figured 39.6cos49.5 should be Vxo, and a = Vxo^2/28.7 m

That gives me Vxo = 25.72 m/s, a = 23.05 m/s^2

I have a suspicion that if something is wrong, it has to do with how I calculated a - am I right?

Anyway, I plugged that into x = xo + Vxo*t + 0.5*a*t^2

Then I found t, and plugged all of the numbers I have into

y = yo + vyo*t - 0.5*g*t^2

of course, vyo = 39.6sin49.5 = 30.112 m/s

I keep getting the wrong answer

Any suggestions? Thanks a ton

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Kinematics Question

**Physics Forums | Science Articles, Homework Help, Discussion**