(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 15.0 kg block is sliding across the floor. Initially, it is moving at 1.2 m/s. However, after sliding 20.0 meters, =7.5 J of work are done on it by friction. What is the block's velocity after sliding 20.0 meters?

2. Relevant equations

KE=.5v^{2}

lw-l=F[tex]\Delta[/tex]Xcos[tex]\theta[/tex]

w+=F[tex]\Delta[/tex]Xcos[tex]\theta[/tex]

3. The attempt at a solution

I found the initial KE to be 10.8 J.

I found the ending IE to be -7.5 J and the KE to be 3.3 J.

With a velocity of 0.66 m/s as the answer, is this correct?

Thanks!

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# Homework Help: Kinetic and Internal Energy

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