Kinetic energy and work problem

AI Thread Summary
A block of ice slides down a frictionless ramp at a 55-degree angle while being pulled by a 54 N force up the ramp. Its kinetic energy increases by 80 J over a distance of 0.400 m. The discussion revolves around calculating how much greater the kinetic energy would have been without the rope, with an initial attempt suggesting a total of 101.6 J. The correct approach emphasizes that the difference in kinetic energy due to the rope's force must be carefully considered to answer the question accurately. Understanding the work done by the rope is crucial for solving the problem correctly.
J-dizzal
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Homework Statement


In the figure here, a block of ice slides down a frictionless ramp at angle θ=55.0 ˚ while an ice worker pulls on the block (via a rope) with a force that has a magnitude of 54.0 N and is directed up the ramp. As the block slides down through distance d = 0.400 m along the ramp, its kinetic energy increases by 80.0 J. How much greater would its kinetic energy have been if the rope had not been attached to the block?

http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c07/fig_7_C.gif

Homework Equations


K=1/2 mv2, w=Fd, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math080.gif, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math082.gif

The Attempt at a Solution


The work done in the positive x dir is -21.6 because the box is sliding down, if the kinetic energy is 80J then 21.6J+80J=101.6J is the total. But this is not right.
http://i1164.photobucket.com/albums/q562/falsovero/20150630_163254_zps9et5lfe6.jpg [/B]
 
Last edited by a moderator:
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J-dizzal said:

Homework Statement


In the figure here, a block of ice slides down a frictionless ramp at angle θ=55.0 ˚ while an ice worker pulls on the block (via a rope) with a force that has a magnitude of 54.0 N and is directed up the ramp. As the block slides down through distance d = 0.400 m along the ramp, its kinetic energy increases by 80.0 J. How much greater would its kinetic energy have been if the rope had not been attached to the block?

http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c07/fig_7_C.gif

Homework Equations


K=1/2 mv2, w=Fd, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math080.gif, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math082.gif

The Attempt at a Solution


The work done in the positive x dir is -21.6 because the box is sliding down, if the kinetic energy is 80J then 21.6J+80J=101.6J is the total. But this is not right.
http://i1164.photobucket.com/albums/q562/falsovero/20150630_163254_zps9et5lfe6.jpg [/B]
What is the correct answer?

Read the question you're asked carefully.
"How much greater would its kinetic energy have been if the rope had not been attached to the block?"​
 
Last edited by a moderator:
its would be 101.6 - 80. would be the difference between the the work with the 54N and without?
 
Read the question you're asked carefully.
"How much greater would its kinetic energy have been if the rope had not been attached to the block?"​
thanks i need to work on this, it gets me often.
 
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