Kinetic energy, work pirnciple. (?)

AI Thread Summary
To determine the average force exerted by a baseball on a fielder's glove, the kinetic energy of the ball is crucial. Given the mass of the baseball (140g) and its speed (32m/s), the kinetic energy can be calculated. As the ball decelerates to rest over a distance of 25cm, the work-energy principle applies, where work done equals the force multiplied by distance. The average force can be derived using the relationship between work and kinetic energy, confirming that both methods yield the same result. Understanding these principles is essential for solving the problem effectively.
heelp
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a base ball (m= 140g) traveling 32m/s moves a fielder's glove backward 25cm when the ball is caught. What was the average force exerted by the ball on the glove?



since w=f||d would it make sense if the average force is f= d/w
I know force =ma but I don't see how to apply it in this problem. I also know that work =m *h* g. but these informations doesn't help me.

you heelp would be appreciated
 
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Maybe the kinetic energy of the ball would be a handy piece of information?
 
The ball decelerated to rest over a distance of 25cm. It's plain old equations of motion.

Edit: Just noticed the title of this thread. You'll get the same answer if you use kinetic energy and w = f*d.
 
Last edited:
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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