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iamtrojan3
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Homework Statement
A block is at rest on a plank whose angle can be varied. The angle is gradually increased from 0 deg. At 26.5°, the block starts to slide down the incline, traveling 3.10 m down the incline in 2.00 s. Calculate the kinetic coefficent of friction between the block and the plank.
Homework Equations
Uk = friction Coefficient
D = Vot + 1/2at^2
F= ma
kinetic Friction = cos(theta)*m*g*Uk
The Attempt at a Solution
First i used the kinematic equation to solve for the acceleration,
3.1 = 0 + 1/2a(2)^2
a = 1.55 m/s^2
Then with the acceleration i got here pluged it in the F= ma to get,
F = m (1.55)
F = sin(theta)*m*g - cos(theta)*m*g*Uk
Notice the m cancels out so i get
Sin(theta)g-Cos(theta)*g*Uk= a
g = 9.8m/s^2
I plugged everything in, theta = 26.5, a = 1.55, g = 9.8 and solved for Uk
Uk turned out to be -.352 which is wrong and makes no sense... but nevertheless, .352 is also wrong.
Any idea on what i did wrong?
thanks for the help!