Kinetic Pressure: Explanation and Questions

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    Kinetic Pressure
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The discussion centers on the calculation of average force exerted by molecules colliding with a wall, questioning the use of round trip time versus collision time. It highlights that the average force is derived from impulse divided by the total time, which includes periods of zero force during travel. Participants suggest that considering a longer duration, like two round trips, could yield different results. The validity of the information from the referenced site and textbooks is acknowledged, but the focus remains on the nuances of the average force calculation. The conversation seeks clarity on the implications of time measurement in kinetic pressure calculations.
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Please visit this site for me. I'm having a little trouble with the explanation.
http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/kinthe.html#c3
Note however that you can find a similar explanation in all textbooks, so I'm in no way questioning the validity of the information.

The average force that the wall exerts on the molecule is impulse/ time (N's second law). But the time they have made use of, is the time for a 'round trip'. Shouldn't it be the time taken for the collision?
Thans
 
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Kenny Lee said:
Please visit this site for me. I'm having a little trouble with the explanation.
http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/kinthe.html#c3
Note however that you can find a similar explanation in all textbooks, so I'm in no way questioning the validity of the information.
The average force that the wall exerts on the molecule is impulse/ time (N's second law). But the time they have made use of, is the time for a 'round trip'. Shouldn't it be the time taken for the collision?
Thans
This is an "average" calculation, assuming there are enough molecules that some are striking the wall at any given time. In terms of individual molecules, the force that one molecule contributes is, say, F during the collision, 0 while it is making the trip to the other wall and back. It's average contribution is the impulse divide by the time of the entire trip. You can, if you like, think of it as "total force"- the actual force times the duration of the collision plus 0 times the duration of the trip- divided by the total time.
 
But couldn't we then make use of the 'average' over a longer period; let's say two 'round trips'. In which case, we would obtain a duration of 4d/v. And a different final result.
Or have I misunderstood?
 
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