Kirchhoff's rules for resistors in parallel

AI Thread Summary
The discussion focuses on applying Kirchhoff's rules to a circuit with resistors in parallel to determine the currents I1, I2, and I3. The circuit includes an emf of 9 V, an internal resistance of 1.5 ohms, and three resistors with values of 5, 15, and 13.75 ohms. The user calculated I1 as approximately 0.9328 A by combining the resistances and considering the battery's resistance. They expressed difficulty in visualizing the current splits and equivalent resistances due to the lab's unconventional presentation of the problem. A suggestion was made to redraw the circuit using standard schematic symbols for better clarity in analysis.
coleman221
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Homework Statement



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Use Kirchoff's rules to determine I1, I2 and I3 for the following circuit:
Use the following values:ε = emf = 9 V
r = internal resistance = 1.5
R1 = 5
R2 = 15
R3 = 13.75

Homework Equations



The Attempt at a Solution


I found I1 to be .9328 by adding all the resistors together (taking into account that r3 was in parallel to r1 and r2) and adding the resistance of the battery.

I've been trying to use 0=ε-I1r-IR1-IR2
0=ε-I1r-I3R3
I1=I2+I3
I've done similar problems but this is for a lab instead of homework so its written in different a way (and they like to throw in things we haven't learned yet in lecture) so i think I'm having trouble visualizing where the currents are splitting and what parts are equivalent.
 
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updated to add correct image
 
Why not redraw the circuit in a more conventional way, using the standard schematic symbols? It might help you to see ways to go about analyzing it.
 
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