Lab Questions on gravitational potential energy and Kinetic Energy

AI Thread Summary
The discussion focuses on calculating maximum power while running up stairs, using mass, height, distance, and time. The change in gravitational potential energy is calculated as 802.62 J, and the average kinetic energy is found to be 27.10 J. Confusion arises in calculating power, with suggestions to use gravitational energy instead of kinetic energy due to the perpendicular nature of the forces involved. The correct approach emphasizes using work derived from gravitational energy for power calculations. Ultimately, the clarification highlights the importance of understanding the relationship between force, distance, and energy in these calculations.
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In this investigation I had to calculate my maximum power as I run up a flight of stairs. These are a few questions that I have for my lab. I want to know if my calculations are right.

Given:

1. mass: 70kg
2. h = 1.17m
3. d= 1.78m
4. t = 2.02s

Use the information from 1 and 2 to find the change in gravitational potential energy.

ΔEG = mgΔh
ΔEG = (70kg) (9.8 N/kg) (1.17m)
ΔEG = 802.62 J


Use the information in steps 1 and 3 to find average kinetic energy.

v = Δd/Δt
v = 1.78m/2.02s
v = 0.88m/s

Ek = mv²/2
Ek = (70kg) (0.88m/s)²/2
Ek = 27.10 J


Using the information in steps 4 and 7 find your power.

W = (27.10J) (1.78m)
W = 23.08 W

P = W/Δt
P = 48.24 J/2.02s
P = 23.88 W
 
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Gravitational energy looks fine. I'm pretty sure your kinetic calculation is all right too, unless they want you to find the total distance traveled (using the height and the horizontal distance). There seems to be some confusion in the third part. Remember Work=FORCE*distance, not energy*distance, and remember the units of force and work are Newtons and joules (units of energy are the same as for work).
 
Is this right for the third part

P = Ek/Δt
P = 27.10 J / 2.02s
P = 13.42 W
 
Well...this is what I think. Remember that the full equation for work is F*d cos theta. If theta is 90 degrees (the force is perpendicular to the distance) cos theta is 0. So, I think you shouldn't use the kinetic energy for this, it is changing perpendicular to the distance you are looking at (the height). Use the change in gravitational energy for this, and you'll be done.
 
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