Lagrangian of a Particle in Spherical Coordinates (Is this correct?)

In summary, the conversation is about setting up the Lagrange equations of motion in spherical coordinates for a particle subject to a force with spherical components. The equations are derived using the general form of the Lagrangian and then the expressions for the three forces in spherical coordinates are given. The equations are then checked for correctness and the next steps are discussed, including substituting variables and finding centrifugal and Coriolis forces. Finally, the use of the spherical gradient for taking derivatives in spherical coordinates is mentioned.
  • #1
Xyius
508
4

Homework Statement


a.) Set up the Lagrange Equations of motion in spherical coordinates, ρ,θ, [itex]\phi[/itex] for a particle of mass m subject to a force whose spherical components are [itex]F_{\rho},F_{\theta},F_{\phi}[/itex].

This is just the first part of the problem but the other parts do not seem so bad.


Homework Equations


Lagrangian equations of motion.
Since the problem doesn't state it is in any uniform conservative field from which it would have a potential function, I assume I use the more general form of the Lagrangian.
[tex]\frac{d}{dt} \frac{∂T}{∂\dot{q}}-\frac{∂T}{∂q}=Q_k[/tex]


The Attempt at a Solution



So my three general forces would be..
[tex]Q_{\rho}=F_{\rho}[/tex]
[tex]Q_{\theta}=\rho F_{\theta}[/tex]
[tex]Q_{\phi}=F_{\phi}[/tex]

The kinetic energy in Spherical coordinates is..
[tex]T=\frac{1}{2}m\left( \dot{\rho}^2 +\rho^2 \dot{\theta}^2+\rho^2 \dot{\phi}^2 sin^2\theta \right)[/tex]
Thus the three equations of motion are..
[tex]\frac{d}{dt} \frac{∂T}{∂ \dot{\rho}}-\frac{∂T}{∂\rho}=Q_k=F_{\rho}[/tex]
[tex]m \ddot{\rho}-m \rho \dot{\rho} \dot{\theta}^2-2 \rho \dot{\rho} \dot{\phi}^2sin^2 \theta=F{\rho}[/tex]
and..
[tex]\frac{d}{dt} \frac{∂T}{∂ \dot{\theta}}-\frac{∂T}{∂\theta}=Q_k= \rho F_{\theta}[/tex]
[tex]\frac{d}{dt}\left( m \rho^2 \dot{\theta}^2 \right)-m \dot{\theta} \rho^2 \dot{\phi}^2sin \theta cos \theta[/tex]
[tex]2m \rho \dot{\theta} \dot{\rho}+m \rho^2 \ddot{\theta}-m \rho^2 \dot{\phi}^2sin\theta cos\theta[/tex]
and finally..
[tex]\frac{d}{dt} \frac{∂T}{∂ \dot{\phi}}-\frac{∂T}{∂\phi}=Q_k=F_{\phi}[/tex]
[tex]\frac{d}{dt}\left( m \rho^2 \dot{\phi}^2 sin^2 \theta \right)[/tex]
[tex]2m \rho \dot{\rho} \dot{\phi}sin^2 \theta+m \rho^2 \ddot{\phi}sin^2 \theta +2m \rho^2 \dot{\phi}\dot{\theta}sin \theta cos \theta[/tex]

Would these be correct? The rest of the problem says to substitute [itex]\dot{\theta}[/itex] for [itex]\omega[/itex] and then find the corresponding centrifugal and Coriolis forces. I do not recall how I would recognize these terms. I know these are both fictitious forces that are only a product of mass times acceleration. Their form is more obvious is polar form though.. If anyone could help me I would very much appreciate it. :]
Thanks!
 
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  • #3
man i hate not being able to edit some posts...

i said that because it does not look like that you differentiated in spherical coordinates
 
  • #4
What do you mean? I started out in Spherical coordinates from the Kinetic energy didn't I? From there on out it was just the chain rule a bunch of times. :eek:
 
  • #5


I would say that your setup of the Lagrangian equations of motion in spherical coordinates looks correct. You have correctly identified the kinetic energy in spherical coordinates and have set up the Lagrangian equations for each coordinate. However, it would be helpful to include the potential energy in your Lagrangian, as it is important in determining the forces in the system.

For the second part of the problem, you would need to substitute ω for θ in your equations and then determine the corresponding centrifugal and Coriolis forces. The centrifugal force is a fictitious force that arises due to the rotation of the coordinate system, and it is given by F_cent = mω^2ρsin^2θ. The Coriolis force, on the other hand, is a fictitious force that arises due to the motion of the particle in the rotating coordinate system, and it is given by F_cor = -2mωρsinθcosθ(dθ/dt). You can then substitute these forces into your equations and solve for the equations of motion.

I hope this helps! Let me know if you have any further questions.
 

Related to Lagrangian of a Particle in Spherical Coordinates (Is this correct?)

What is the Lagrangian of a Particle in Spherical Coordinates?

The Lagrangian of a particle in spherical coordinates is a mathematical expression that describes the energy of a particle in a system with spherical symmetry. It takes into account the kinetic energy and potential energy of the particle in three-dimensional space.

How is the Lagrangian of a Particle in Spherical Coordinates different from other coordinate systems?

The Lagrangian of a particle in spherical coordinates is different from other coordinate systems because it takes into account the unique shape and symmetry of spherical coordinates. This means that the equations used to calculate the Lagrangian will be different from those used in other coordinate systems.

What are the advantages of using the Lagrangian of a Particle in Spherical Coordinates?

One advantage of using the Lagrangian of a particle in spherical coordinates is that it simplifies the equations used to describe motion in three-dimensional space. It also allows for a more intuitive understanding of the system, as the spherical coordinates correspond to physical parameters such as radius and angle.

How is the Lagrangian of a Particle in Spherical Coordinates derived?

The Lagrangian of a particle in spherical coordinates is derived using the Lagrangian formalism, which is a mathematical framework for describing the dynamics of a system. It involves setting up the Lagrangian function and using the Euler-Lagrange equations to solve for the equations of motion.

What real-world applications does the Lagrangian of a Particle in Spherical Coordinates have?

The Lagrangian of a particle in spherical coordinates has various applications in physics and engineering, such as in celestial mechanics, fluid dynamics, and electromagnetism. It is also used in fields such as robotics and aerospace engineering to model the motion of objects in three-dimensional space.

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