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Lagrangian of Standard Model Deduction

  1. May 23, 2015 #1
    Does anyone know where can I find the deduction of all terms of the updated SM lagrangian? Although I have already looked at some lagrangians and theories like local gauge invariance, Yang-Mills theory, feynman rules, spontaneous symmetry-breaking and others, I wanted to see the deduction and simplification of the updated SM lagrangian.

    Thank you,
    Jorge.
     
  2. jcsd
  3. May 23, 2015 #2

    Orodruin

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    What do you mean by "deduction"? The Standard Model is postulated and tested against experiment. It was postulated on the basis of several experimental observations of the different interactions.
     
  4. May 23, 2015 #3
    When I said deduction I was thinking of the mathematics behind the SM Lagrangian. Probably deduction wasn't the best word to use, instead I should have said "mathematical background".
     
  5. May 23, 2015 #4

    Orodruin

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    It is essentially nothing else than a spontaneously broken Yang-Mills theory with the gauge group SU(3)xSU(2)xU(1) with a bunch of fermion fields transforming under different representations of the gauge groups.
     
  6. May 23, 2015 #5
    Summed up looks easy xD
    I will work on that, thank you for the reply.
     
  7. May 23, 2015 #6

    ChrisVer

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    I don't think you can deduce it out of somewhere... you take your local symmetries and create invariant objects under those symmetry transformations. The thing is that nothing (at least only by that principle) to write down many terms or insert different things. But if you write down some representations you'll have:
    [itex] (3 , 1,1) [/itex] : a triplet under SU(3) alone, and SU(2) singlet . Here you can have right handed quarks, since they don't see the weak sector
    [itex] (3, 2, 1) [/itex] : a triplet under SU(3), a doublet under SU(2). Here you can have left handed quarks , which can interact under both strong and weak interactions.
    [itex] (8, 1, 1)[/itex] : the gauge bosons of SU(3)
    [itex] (1, 3,1 )[/itex] : the gauge bosons of SU(2)
    [itex](1,1,1)[/itex] : Here you can have the right handed fermions.
    [itex] (1, 2, 1) [/itex] :colorless SU(2) doublets... here you can have the Higgs or the left handed leptons.
    The last 1 in the parenthesis could as well be changed...it's in fact the hypercharge of the particle (but because this can change from particle to particle I just wrote 1)
    in a notations [SU(3) , SU(2), U(1)]... I don't know if I forgot anything...
    Also for the SU(3) triplets you must have in mind that [itex]3[/itex] could as well be [itex]\bar{3}[/itex] (the complex repr). For SU(2) that's not the case, since [itex]2 \equiv \bar{2}[/itex].

    One example to get an idea of a term, is to write down a mass term for the leptons... In that case you need something like : [itex] m \bar{\psi}_L \bar{\psi}_R[/itex] which means you need to mix the left and right handed leptons... going to the above scheme you have to make an invariant object with:
    [itex](1,2,Y_1) [/itex] and [itex](1,1,Y_2)[/itex]. The result of those two would be [itex](1,2,Y_1) \otimes (1,1,Y_2) = (1,2,Y_1+Y_2)[/itex]
    In order to make an invariant object with those two, you need an extra SU(2) doublet (because a [itex]2\otimes 2=3 \oplus 1[/itex] contains the singlet) and with hypercharge [itex]-Y_1 -Y_2[/itex] - and that's the role for the Higgs... As a result you obtain the lepton Yuawa terms.
    The result of those three combinations would have to be [itex](1,1,0)[/itex]
     
    Last edited: May 23, 2015
  8. May 27, 2015 #7

    vanhees71

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