Laplace Transform for a circuit

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Discussion Overview

The discussion revolves around finding the Laplace transform of a specific signal, xa(t) = 2u(t-1), as part of a circuits homework assignment. The focus is on understanding the application of Laplace transforms in the context of circuit analysis.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant seeks clarification on the Laplace transform of the signal, specifically questioning the role of the unit step function u(t-a).
  • Another participant confirms that u(t-c) is indeed a unit step function and mentions the linearity property of the Laplace transform.
  • A third participant attempts to apply the information by suggesting a potential expression for the Laplace transform, 2*e^(-s)/s, based on the previous confirmation.
  • A later reply simply agrees with the previous suggestion without further elaboration.

Areas of Agreement / Disagreement

Participants generally agree on the identification of the unit step function and the linearity of the Laplace transform. However, the discussion does not reach a consensus on the final expression for the Laplace transform.

Pete_01
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Homework Statement


It's been a while since I've done laplace transforms, but I need some help with one!
I am supposed to find the laplace tranform for the following signal. This is for my circuits class btw.

xa(t) = 2u(t-1)


Homework Equations



Laplace tables. http://tutorial.math.lamar.edu/Classes/DE/Laplace_Table.aspx

The Attempt at a Solution


I am guessing that the u(t-a) part is a unit step function correct? From there, I am not exactly sure how to go. I don't see any transforms that fit exactly.
 
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#25 is u(t - c). Yes, this is a unit step function.

And L{kf(t)} = kL{f(t)} because of the linearity of the Laplace transform.
 
Thanks for the reply mark!
So using 25, I would have 2*e-s/s ?

Mark44 said:
#25 is u(t - c). Yes, this is a unit step function.

And L{kf(t)} = kL{f(t)} because of the linearity of the Laplace transform.
 

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