Laplace Transform for a circuit

  • Engineering
  • Thread starter Pete_01
  • Start date
  • #1
51
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Homework Statement


It's been a while since I've done laplace transforms, but I need some help with one!
I am supposed to find the laplace tranform for the following signal. This is for my circuits class btw.

xa(t) = 2u(t-1)


Homework Equations



Laplace tables. http://tutorial.math.lamar.edu/Classes/DE/Laplace_Table.aspx

The Attempt at a Solution


I am guessing that the u(t-a) part is a unit step function correct? From there, I am not exactly sure how to go. I don't see any transforms that fit exactly.
 

Answers and Replies

  • #2
35,301
7,170
#25 is u(t - c). Yes, this is a unit step function.

And L{kf(t)} = kL{f(t)} because of the linearity of the Laplace transform.
 
  • #3
51
0
Thanks for the reply mark!
So using 25, I would have 2*e-s/s ?

#25 is u(t - c). Yes, this is a unit step function.

And L{kf(t)} = kL{f(t)} because of the linearity of the Laplace transform.
 
  • #4
35,301
7,170
Yes.
 

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