Laplace Transform for Functions: 5cos(7t+π/4) and e^(3t)sintcost

skrat
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Homework Statement


Find Laplace transformation for functions ##f(t)##:
a) ##5cos(7t+\pi /4)##
b) ##e^{3t}sintcost##

Homework Equations


The Attempt at a Solution



a) I know that for ##cos(\omega t)## the laplace is ##\frac{s}{s^2+\omega ^2}## but what can I do with that ##\pi /4## ?

I believe I would have to use this identity ##f(t)^{'}=sF(s)+f(0)## but I don't know how o use it...

Could somebody please show me that?
 
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skrat said:

Homework Statement


Find Laplace transformation for functions ##f(t)##:
a) ##5cos(7t+\pi /4)##
b) ##e^{3t}sintcost##


Homework Equations





The Attempt at a Solution



a) I know that for ##cos(\omega t)## the laplace is ##\frac{s}{s^2+\omega ^2}## but what can I do with that ##\pi /4## ?

I believe I would have to use this identity ##f(t)^{'}=sF(s)+f(0)## but I don't know how o use it...

Could somebody please show me that?

Use the addition formula for ##\cos(a+b)## before taking the transform.
 
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OMG, How can I be so stupid! -.-

Thanks LCKurtz!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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