LaPlace Transform of Heavy Side Function Homework

  • Thread starter Thread starter TG3
  • Start date Start date
  • Tags Tags
    Function
TG3
Messages
66
Reaction score
0
Homework Statement
While t<1 , f(t) =0
While t>= 1, f(t) = t^2-2t+2
Find the LaPlace transform of the given function.
The attempt at a solution
The problem can be re-written as: u1(t)(t^2-2t+2)

If it helps, this in turn can be re-written as: u1(t)((t-1)^2+1). I'm not sure it does help though.

As for how to proceed from here, I'm in a fog. I know the LaPlace transform for something of the form uc(t) y(t-c), but have no idea what to do with this problem because of the raised power.
 
Physics news on Phys.org
Don't you have the formula for L(tn)?

Or the formula for L(t*f(t)) in terms of L(f(t))?

Oh, and the guy's name was Heaviside. He likely wasn't heavy on one side. :smile:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top