Laser Beam - Divergence and Solid Angle

AI Thread Summary
The discussion focuses on the relationship between beam divergence and solid angle in laser physics. Participants express confusion about how to calculate solid angle from divergence, despite understanding the definitions of both terms. It is noted that the solid angle can be derived from the divergence angle by considering the cone formed by the beam and its intersection with a sphere. The conversation includes references to relevant equations and resources, emphasizing the need for clarity on how to apply these concepts practically. Ultimately, the participants seek a straightforward method to relate beam divergence to solid angle calculations.
Naz93
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I am somewhat confused about the connection between divergence and solid angle for a beam. I know individually what each term means... but I'm confused as to how (or even if) one can calculate the solid angle of a beam, given the divergence.

I have some notes from a previous lecture series I attended on laser physics, where I wrote down: "Laser radiation has a narrow divergence (~1mrad), and so a small solid angle (~10^-6∏ sterad)". That seems to imply that the divergence is sufficient information to calculate the solid angle of the beam... but I just can't seem to do it.

(I'm not concerned just with the numbers given here, but rather the general problem of how to relate solid angle and beam divergence)

Thanks!
 
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Are you looking for an equation? Or do you need help understanding an existing equation?
 
I don't know of an equation to calculate solid angle from beam divergence... I only know solid angle by the definition dΩ=sinθ*dθ*dø

I feel like I'm missing something obvious here...
 
Hmm, that kind of explains it. All I'm really after is a way to calculate a number for the solid angle of a beam, given a number for the divergence of the beam... I'm still not sure how to do this
 
the equation above looks correct. Are you looking for theta or phi? Or are you trying to figure out how to solve the eq above?
 
Well... I don't know what theta or phi even are in relation to the beam divergence. The equation is a correct expression for a solid angle in terms of the two polar angle coordinates, but I don't see how it helps in finding the solid angle given a beam divergence...
 
Divergence angle is used because it is relatively easy to measure given that the beam has a circular profile. The formulas given in the article are for the ideal Gaussian beam, which is often, but not always what is output from a laser.

For the simplest application just determine the diameter of the circle which contains 90% of the beam power (or your favorite proxy for beam width) at two points sufficiently far apart. Then apply the formula pointed out by rigetFrog.
 
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  • #10
Thanks both. The formula would then give the divergence, calculated from the two beam diameters and the distance between them... but then I'm still confused how to get the solid angle of the beam from the divergence. I think I'm just confused what a solid angle even is...
 
  • #11
Naz93 said:
Thanks both. The formula would then give the divergence, calculated from the two beam diameters and the distance between them... but then I'm still confused how to get the solid angle of the beam from the divergence. I think I'm just confused what a solid angle even is...

The cone of revolution about the central ray of the beam, whose angle is the divergence angle, will intersect the surface of every sphere whose center is the apex of the cone.

The solid angle is the ratio of the surface area enclosed by the cone to the total surface area of the sphere. Pick the distance R=1 as being the most convenient surface.

Solid angle: https://en.wikipedia.org/wiki/Solid_angle
 
  • #12
But how to project a circle onto the curved surface of a sphere? Is the way to actually calculate a solid angle to use the equation on wikepedia (integral of sin(theta)d(theta)d(phi) ) with the limits of theta and phi both set to the divergence angle?
 
  • #14
Amazing, thanks! That's a really nice explanation :-)
 
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