Laser refraction through curved surface and water

Click For Summary

Discussion Overview

The discussion centers on the refraction of a Nd:Yag laser as it passes through a cylindrical acrylic tube filled with water. Participants explore the effects of the curved acrylic surface on the laser beam's path and how to apply Snell's law to various angles of incidence. The conversation includes both theoretical considerations and practical implications for the setup.

Discussion Character

  • Exploratory
  • Technical explanation
  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant seeks to understand the refraction of a laser beam as it transitions from air to acrylic and then to water, mentioning specific refractive indices and dimensions of the setup.
  • Another participant suggests that if the acrylic is thin, it might be reasonable to ignore it and focus on the water's refractive index, questioning the significance of the acrylic's curvature.
  • There is a discussion about whether the laser will always hit the cylinder at the same point or if the entry point will vary with angle, which could affect the analysis.
  • A participant proposes using ray matrices to analyze the problem, noting that the acrylic and water could also affect the beam's spread due to their cylindrical lens properties.
  • One participant provides an introduction to the ray transfer matrix approach, explaining how to characterize a ray and how to apply matrices for refraction and straight-line travel through different media.
  • Specific matrix forms for refraction at curved interfaces are discussed, along with a reference to additional resources for further exploration of ray transfer matrices.

Areas of Agreement / Disagreement

Participants express differing views on the significance of the acrylic's curvature and whether it can be neglected in calculations. The discussion remains unresolved regarding the best approach to analyze the refraction through the curved surface.

Contextual Notes

Participants mention specific assumptions about the thickness of the acrylic and the angles of incidence but do not resolve the implications of these assumptions on the overall analysis.

bregazzi
Messages
3
Reaction score
0
Hello everyone, hope you can help me! I am doing research involving illumination of an object in a cylindrical acrylin tube filled with water using a Nd:Yag laser.

Homework Statement


I am trying to figure out the refraction of the laser as it passes from air through the curved acrylic then on into the water.
See attached image ;)


Homework Equations


So far I have tried to apply Snells law in several different variations but cannot seem to make sense of the results. Ideally I want to be a ble to tabulate the affect of the laser entering at any angle from 0-90Deg to the acrylic surface.


The Attempt at a Solution



n for air = 1.000277
n for acrylic = 1.492
n for water = 1.3330
inner dia of tube = 100mm
outer dia of tube = 110mm
thickness of target black body 30mm
 

Attachments

Science news on Phys.org
Welcome to Physics Forums.

[STRIKE]If the acrylic is reasonably thin, you could ignore it and just use the refractive index of water. What is the acrylic thickness, and what is the diameter of the cylinder?[/STRIKE] (EDIT: just read Post #1 more carefully. Acrylic thickness is 10% of the radius, so ignoring it wouldn't be a terrible approximation. I'll have to think about this some more.)

Does the laser always hit the cylinder at the point directly opposite the object, and only the angle will change? Or will the location where the laser hits the cylinder change as well?

p.s. I have moved this thread out of the Homework area of the forums, since it is not homework.
 
Thanks for the reply and sory about the thread being in the wrong place...wasn't too sure where to put it!

The laser will always enter as in the diagram, perpendicular to the cylinder if that makes sense!

I want to find the effect if any the acrylic has on the beam in this position and then for other angles should the laser not be positioned correctly. I have done out a table for refraction from air to acrylic then onto water for planar surfaces but will the fact that the acrylic is not planar have a large impact on the refraction?

AIR TO ACRYLIC
Angle of Incidence Angle of Refraction
0.00 0.00
5.00 3.35
10.00 6.69
15.00 9.99
20.00 13.26
25.00 16.46
30.00 19.59
35.00 22.62
40.00 25.53
45.00 28.30
50.00 30.90
55.00 33.31
60.00 35.49
65.00 37.42
70.00 39.05
75.00 40.36
80.00 41.32
85.00 41.90
90.00 42.10

ACRYLIC TO WATER
Angle of Incidence Angle of Refraction

0.00 0.00
3.35 3.75
6.69 7.49
9.99 11.20
13.26 14.87
16.46 18.49
19.59 22.04
22.62 25.49
25.53 28.84
28.30 32.05
30.90 35.09
33.31 37.93
35.49 40.53
37.42 42.85
39.05 44.84
40.36 46.45
41.32 47.65
41.90 48.38
42.10 48.62
 
Sorry I haven't had much time this week to look into this more. If the laser beam is going to be close to the central "optic axis" of your system, then using ray matrices would be a good way to solve the problem.

Besides being deflected, the acrylic and water could also change the amount of spread in the beam, since they act as a cylindrical lens -- especially the water.

I should have some time later to explain more about the ray matrices, if you like. You can also try googling:

"abcd matrix" optics​
 
I'm assuming you're unfamiliar with the ray transfer matrix approach, so I'll give a a little introduction first.

At any point, a ray is characterized by two parameters: (1) it's displacement from the optical axis, and (2) the angle it makes w.r.t. the optical axis. So we write the ray in terms of the column vector,

v = \left[ \ \stackrel{y}{\theta} \ \right]​

A few things to know about the ray vector:

  • The angle θ is small, so θ ≈ sinθ ≈ tanθ
  • At a medium interface, the angle of the ray changes due to refraction.
  • When the ray travels some distance through a medium without encountering an interface, the displacement changes but the angle does not

Any of these changes -- encountering an interface, or traveling some distance -- are described by a matrix that multiplies the ray vector. For example, over a distance D, the ray's displacement changes from y1 to y1+D·θ. We can write

y2 = y1 + Dθ1
θ2 = θ1

Or, in matrix form,

<br /> \left[ \stackrel{y_2}{\theta _2} \right] = \left[ \stackrel{1}{0} \ \stackrel{D}{1} \right] \ \left[ \stackrel{y_1}{\theta _1} \right]<br />​

Now on to your problem. A ray is incident on the acrylic with initial displacement and angle yi and θi. Taking things one step at a time:
  • First, the ray is refracted at the air-acrylic interface
  • Then the ray travels in a straight line through the thickness of the acrylic
  • Next, the ray is refracted at the acrylic-water interface
  • Finally, the ray travels in a straight line through the water to the sample
Each of those steps is described by a matrix, so we can write for the final ray

vf = Mwater · Macrylic-water · Macrylic · Mair-acrylic · vi
Where each M is the matrix for either a refraction or traveling in a straight line. Note that Mair-acrylic is the first matrix to operate on vi, then Macrylic, and so on.

That is a basic outline of how to solve this problem. For completeness I'll write the matrix for traversing a curved interface, from a medium of refractive index n1 into a medium with index n2, where R is the radius of curvature of the interface:

M =<br /> \left[ \stackrel{1}{\frac{1}{R}\left(\frac{n_1}{n_2}-1\right)} \ \ \ \ \stackrel{0}{\frac{n_1}{n_2}}\right]<br />​
I'm not sure how to write the matrix more neatly, but the upper-left element is 1 and the upper-right element is 0. Also, take R to be a positive value for your example.

A more complete list of matrices can be found here:

http://en.wikipedia.org/wiki/Ray_transfer_matrix_analysis#Table_of_ray_transfer_matrices

Hope that helps; post back with questions if you have any.
 
Last edited:

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
2
Views
4K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
2
Views
2K