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## Homework Statement

What mass of steam at 100 Celcius must be added to 1.00 kg of ice at 0 Celcius to yield liquid water at 20 Celcius.

## Homework Equations

Q = mL

Q = mc(deltaT)

change in energy = 0

## The Attempt at a Solution

Ice

m= 1.00

c = 2100

T1 = 0

Tf =

L = 333

water

m=

c = 4190

T1 =

Tf= 20

Steam

m = ?

c = 2010

L = 2260

T1 = 100

Tf =

I am stil missing some of the needed information and i am not sure how to organize my equations.