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Latent Heat of Vaporization

  1. Mar 4, 2008 #1
    1. The problem statement, all variables and given/known data

    What mass of steam at 100 Celcius must be added to 1.00 kg of ice at 0 Celcius to yield liquid water at 20 Celcius.


    2. Relevant equations

    Q = mL
    Q = mc(deltaT)
    change in energy = 0

    3. The attempt at a solution

    Ice
    m= 1.00
    c = 2100
    T1 = 0
    Tf =
    L = 333

    water
    m=
    c = 4190
    T1 =
    Tf= 20

    Steam
    m = ????
    c = 2010
    L = 2260
    T1 = 100
    Tf =

    I am stil missing some of the needed information and i am not sure how to organize my equations.
     
  2. jcsd
  3. Mar 5, 2008 #2

    Shooting Star

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    Homework Helper

    Divide into two parts.

    How much heat is needed to melt the ice?

    How much heat is needed to raise the temp of this water from 0 C to 20 C?

    This whole heat is supplied by a certain amount of steam, which first gives up the latent heat of evaporation, and then cools from 100 c to 20 C. Equate this to the sum of the first two.

    (Remember, there are two kinds of latent heat involved here. Don't mix them up)
     
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