Lattice constant, space between planes?

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SUMMARY

The discussion focuses on calculating the lattice constant, effective radius of an atom, surface density on the 110 plane, and the distance between two nearest parallel 110 planes in a body-centered cubic lattice with a volume density of 5.3 x 1022. The lattice constant is determined to be 4.25 Å using the equation 4/a3 = volume density. The effective atom radius requires clarification on the multiplicative factor, while the surface density on the 110 plane is calculated using the formula 2/(sqrt2 * (4.25 x 10-8)2). The distance between planes can be derived from geometric principles or the reciprocal lattice vector.

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  • Understanding of body-centered cubic lattice structures
  • Familiarity with lattice constants and atomic radii
  • Knowledge of surface density calculations in crystallography
  • Basic principles of reciprocal lattice vectors
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Homework Statement



the volume density of a body centered cubic lattice is 5.3*10^22

Calculate the lattice constant, effective radius of atom, surface density on 110 plane, and distance between two nearest parallel 110 planes.

Homework Equations


4/a^3= volume density
2/sqrt2*a^2

The Attempt at a Solution


5.3*10^22=4/a^3, a=4.25 A

2) effective atom radius, I know its( r1+r2) but I do not know what factor its multiplied by(i.e. 4*(r1+r2)/sqrt3, 2...) and I think I could solve for r^2 instead of r1 and r2.

3) 2/(sqrt2*(4.25*10^-8)^2) = surface density?

4) I do not know how to find distance between planes, is this r*2 ?
 
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For 2, you need to know the positions of two nearest neighbors. If you take an atom in the corner, where is its nearest neighbor?
For 3, what is a 110 plane for a cubic lattice? Can you draw it?
You can calculate the distance between planes either from geometry or by using the magnitude of the reciprocal lattice vector with the same indices.
 

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