Laws of Forces and Motion: Block Sliding Down an Incline

AI Thread Summary
A block of mass 2.00 kg is released from a height of 5 m on a frictionless incline at a 30-degree angle. The discussion covers calculating the block's acceleration while sliding down, its velocity upon leaving the incline, and its trajectory as it falls from the table. Key equations include F = ma for acceleration and kinematic equations for velocity and position. The transition from sliding down the incline to projectile motion is emphasized, noting that once the block leaves the incline, only gravitational acceleration affects its motion. Understanding these concepts is crucial for solving the problem accurately.
saber1357
Messages
67
Reaction score
1
1. Homework Statement

A block of mass m=2.00kg is released from rest at h=5m above the surface of the table, at the top of a theta=30 degrees incline. The frictionless incline is fixed upon a table with a height of 2.0m. a) determine acceleration as it slides down the incline.
b)What is velocity of block as it leaves incline?
c) How far from the table will the block hit the floor?
d)what time interval elapses.

2. Homework Equations
a) F = ma, a = F/m
b) Vf^2 = Vi^2 + (2*a*position)
c) ?
d) position = Vi + 1/2*a*t^2

3. The Attempt at a Solution
I figured out part a, the acceleration, and part b, the velocity at which the object left the incline. However, as soon as the object leaves the incline, it begins falling off the table. If I'm suppose to separate this part of the question into vector components, how would I go about doing that? Can I use the acceleration I found in a) as the horizontal acceleration?
 
Physics news on Phys.org
Once the object leaves the incline and starts falling, it becomes a projectile just like any other. What must its acceleration be?
 
Acceleration due to gravity, however, since the particle was accelerating to begin with, does that play a role in anything?
 
Not once it leaves the incline and start falling. (Any force that the incline was exerting on the object stops acting as soon as the object loses contact with the incline.)
 
Understood! Thank you!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top