- #1

AiRAVATA

- 173

- 0

Imagine a voltage source [itex]V_0[/itex], a capacitor [itex]C[/itex] and an inductor [itex]L[/itex], all hooked up in series. I know that the equation governing the behvior of the system is

[tex]V_0=\frac{1}{C}q(t)+L\ddot{q}(t),[/tex]

and hence

[tex]q(t)=A\cos \omega t + B\sin \omega t + CV_0.[/tex]

What I'm having trouble with is the initial conditions. Is it fair to assume that in [itex]t=0[/itex] there is no charge nor current in the system?

If I put a switch in the system, how would the initial conditions change (assuming is open in [itex]t=0[/itex] and closed in [itex]t>0[/itex])?