LC circuit Oscillatiing current

AI Thread Summary
An LC circuit consists of a 33 pF capacitor charged by a 6V battery and a 15 mH inductor. When the switch is moved to position b, the capacitor discharges through the inductor, leading to oscillations. The resonant frequency is calculated using the formula w = 1/sqrt(LC), and the impedance is determined by Z = |XL - XC|. The maximum oscillating current can be derived from energy conservation principles, where the energy stored in the capacitor converts to energy in the inductor. Understanding the relationship between current and energy storage is crucial for solving the problem effectively.
lpau001
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Homework Statement



An LC circuit is shown in the figure below. the 33 pF capacitor is initially charged by the 6V battery when S is at position a. Then S is thrown to position b so that the capacitor is shorted across the 15 mH Inductor.


Homework Equations



w= 1/sqrt(LC)

XL = wL

xC = 1/(wC)


The Attempt at a Solution



I didn't know where to start really, so I tried googling the problem and eventually I found that apparently

Z= |XL - XC|

But when I try to do these, my XL and XC are equal to each other, so I get 0. is this correct??
 
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I don't see a question to be answered in the problem statement.
 
ahh yea, that would make things a little difficult. Sorry.

What is the maximum value for the oscillating current assuming no resistance in the circuit?
 
lpau001 said:
ahh yea, that would make things a little difficult. Sorry.

What is the maximum value for the oscillating current assuming no resistance in the circuit?

And then there was light!

Look at it in terms of energy storage. When the capacitor is initially fully charged, it's holding onto all the available energy in a "static" state as electrical potential. When the charge on the capacitor is (briefly) zero, all the energy will be stored in the inductor's field with the maximum current running through it. Tie together the current and the energy.
 
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