Le^x-(1+x/1+x^2/2)l <= e/6 for all x E [0,1].

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I have a problem.
How do I show that le^x-(1+x/1!+x^2/2!)l <= e/6 for all x E [0,1].
 
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Show that the equation is true at the boundries. Show that the term on the left is monotonic in x (if, indeed, it is).
 


What a strange coincidence. I saw this thread only after posting my example in this thread.

If you don't want to see the full solution, here's a hint: Taylor's theorem.
 


how to show that a function is monotonic increasing? show that f(x+1) >= f(x) for all x?
 


ice109 said:
how to show that a function is monotonic increasing? show that f(x+1) >= f(x) for all x?

No, that won't work. A function is monotonic increasing if f(x) ≥ f(y) whenever x ≥ y.
 

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