Physics Homework: Calculating Motorcycle Jump Distance Without Air Resistance"

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The discussion revolves around a physics problem involving projectile motion, specifically calculating the speed required for a motorcycle to jump across a 40 m wide river from a ramp inclined at 53 degrees, with the far bank 15 m lower. Participants are seeking equations that relate x-displacement, y-displacement, angle of projection, and initial velocity to solve for the necessary speed and landing position if the speed is halved. The equations of motion provided include components for horizontal and vertical displacement. There is a struggle to apply the correct projectile motion equations effectively. The conversation highlights the complexities of calculating jump distances without considering air resistance.
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Homework Statement


A physics professor is attempting to jump across a river on a motorcycle. The takeoff ramp was inclined at 53 degrees, the river was 40 m wide, and the far bank was 15 m lower than the top of the ramp. Ignoring air resistance, a) what should his speed have been at the top of the ramp to have just made to the far edge of the bank. If his speed was only half the value found in a), where did he land?



Homework Equations


vx=v0cosa0
vy=vysina0



The Attempt at a Solution



I tried a bunch of methods..all came out wrong:( Help please. I made a drawing for reference..
 

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Can you find an equation of projectile motion which gives the relation between x-displacement, y- displacement, angle of projection and initial velocity?
 
rl.bhat said:
Can you find an equation of projectile motion which gives the relation between x-displacement, y- displacement, angle of projection and initial velocity?

No not really :frown:
 
OK.
y = x[tan(theta)] - g*x^2/2[Vo*cos(theta)]^2
 

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