Legendre differential equation and reduction of order

CassieG
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Homework Statement



Question is to find a general solution, using reduction of order to:

(1-x^2)y" - 2xy' +2y = 0

(Legendre's differential equation for n=1)

Information is given that the Legendre polynomials for the relevant n are solutions, and for n=1 this means 'x' is a solution.

Homework Equations



See above.

The Attempt at a Solution



'x' is one solution, I need another to form the general solution. I tried solving the characteristic equation in terms of x, as shown at this link. http://www.bravus.com/Legendre.jpg

I've included all the information from the question, any guidance in the right direction would be very welcome.
 
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You just need one solution to reduce the order so let y_1=x and y=y_1 v in your equation written as:

y''+py'+qy=0

do all that substituting and letting v'=w you should get:

y_1 w'+(2y_1^'+p y_1)w=0

which you can solve via an integrating factor.
 
That makes a lot of sense. Just working through it now, but I think it was realising I *had* reduced the order and had a first order ODE and then solving with the integrating factor was the point I was missing.

Thanks very much.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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