[LENS] Given focal length and height, find object distance

AI Thread Summary
To find the object distance in front of a convex mirror, the magnification (M) is established as 0.25, indicating the image height is 25% of the object height. Using the magnification formula, the relationship between the object distance (p) and image distance (q) is determined, revealing that p equals four times q. The relevant lens equation, 1/p + 1/q = 1/f, is then applied, with the focal length (f) given as 0.2m. Proper attention to the signs for the focal length and image distance is crucial for accurate calculations.
Phil123
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Homework Statement


An object is in front of a convex mirror. We then obtain an erect image whose height is equal to 25% of the height of the object. What is the distance between the object and the mirror if we know that the focal distance is equal to 0.2m?

Homework Equations


M = Yi/Yo = q/p
1/p+1/q=1/f

Yi= height of the image
Yo = height of the object
q = distance of the image
p= distance of the object
M = magnification
f = focal distance

The Attempt at a Solution



M = Yi/Yo = 0.25 since the image is 25% the height of the object.
Then, since M=q/p, I know the distance from the object to the mirror is 4 times the distance of the image to the mirror.
This is where I'm stuck.
 
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Phil123 said:

Homework Statement


An object is in front of a convex mirror. We then obtain an erect image whose height is equal to 25% of the height of the object. What is the distance between the object and the mirror if we know that the focal distance is equal to 0.2m?

Homework Equations


M = Yi/Yo = q/p
1/p+1/q=1/f

Yi= height of the image
Yo = height of the object
q = distance of the image
p= distance of the object
M = magnification
f = focal distance

The Attempt at a Solution



M = Yi/Yo = 0.25 since the image is 25% the height of the object.
Then, since M=q/p, I know the distance from the object to the mirror is 4 times the distance of the image to the mirror.
This is where I'm stuck.
Use the equation you included 1/p+1/q=1/f. Take care of the signs of focal length and image distance.
 
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