Lense/Image help (interactive diagram fun)

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The discussion revolves around using an interactive lens diagram to calculate the focal length and the distance needed between a lens and an object for the image to be the same size as the object. The lens maker's equation is applied, leading to a focal length of 0.83 m (or 83 cm). Participants confirm that using the thin lens equation, the distances p and q should both equal 166 cm. Clarifications are provided that this distance represents the separation between the lens and the arrow. The thread emphasizes the importance of correctly applying lens equations for accurate optical calculations.
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Hello, I have some questions dealing with an interactive diagram. to access the diagram go here: http://www.colorado.edu/physics/phet/simulations/lens/lens.swf
when you go there set the radius of curvature to 1.0 m, the refractive index to 1.6, and the diameter to 1.2 m

Ok first question:1. Calculate the focal length of the lens. So I know I need to use the lens maker's equation. 1/f = (n-1) (1/R1 - 1/R2)
Plugging in numbers is the answer: .83 cm?

2. Calculate the distance you need between the lens and the arrow so that its image is the same size as the object. What are your calculated values of p and q?
What equation do I use to calculate this distance?


Please help, muchas gracias.
 
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nophun6 said:
Ok first question:1. Calculate the focal length of the lens. So I know I need to use the lens maker's equation. 1/f = (n-1) (1/R1 - 1/R2)
Plugging in numbers is the answer: .83 cm?
Your distance is in meters, so that's 0.83 m = 83 cm.

2. Calculate the distance you need between the lens and the arrow so that its image is the same size as the object. What are your calculated values of p and q?
What equation do I use to calculate this distance?
Look up the thin lens equation.
 
Ok the thin lens equation : 1/p + 1/q = 1/f
f= 83 cm correct?
So would that mean that p and q = 166cm ? Or is that the distance between the lens and the arrow ?
please help
 
nophun6 said:
Ok the thin lens equation : 1/p + 1/q = 1/f
f= 83 cm correct?
Right.
So would that mean that p and q = 166cm ?
Right.
Or is that the distance between the lens and the arrow ?
Also right.
 
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