Calculating Tension in a 6-kg Bucket Being Pulled Up by a String

AI Thread Summary
The discussion centers on calculating the tension in a rope pulling a 6-kg bucket of water at a constant speed. The correct tension is determined to be about 60 N, as the bucket is in equilibrium with no net acceleration. Some participants initially suggested that the tension could be 0 N, but this was clarified as incorrect since the bucket would fall without tension. The relevant equations, including ΣF=ma and T=ma+mg, were referenced to support the calculations. Overall, the consensus is that the tension in the rope is indeed 60 N.
1man
Messages
16
Reaction score
0

Homework Statement


A 6-kg bucket of water is being pulled straight up by a string at a constant speed.

What is the tension in the rope?

about 42 N
about 60 N
about 78 N
0 N because the bucket has no acceleration.

Homework Equations


\SigmaF=ma
ma=T-mg
T=ma+mg

The Attempt at a Solution



I get about 60 but I want to be sure before I submit this answer. can someone please check my work to make sure i am right?
 
Physics news on Phys.org
No its 0N any constant acceleration is in equilibrium therefore the net force is equal to 0. W=FD W=0
 
im looking for the tension and the tension wouldn't be 0 because if it were the bucket would be falling
 
sorry should have read your question better 60N is right for the tension.
 
1man said:

Homework Statement


A 6-kg bucket of water is being pulled straight up by a string at a constant speed.

What is the tension in the rope?

about 42 N
about 60 N
about 78 N
0 N because the bucket has no acceleration.

Homework Equations


\SigmaF=ma
ma=T-mg
T=ma+mg

The Attempt at a Solution



I get about 60 but I want to be sure before I submit this answer. can someone please check my work to make sure i am right?

i say 60N aswell
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

How much work is done on a bucket when pulling it up?
Replies
3
Views
2K
What is the tension in the lift cable and in the string?
Replies
19
Views
3K
Force pulling on a string at an angle with a block at the other end
Replies
2
Views
1K
Bead on a rod which is being pulled by an ideal string with velocity v
Replies
27
Views
996
Tension on a Massive Rope: How to Calculate Tension at Different Points
Replies
11
Views
3K
Work Pulley Problem with constant speed
Replies
2
Views
1K
Pulling yourself up with a pulley
Replies
9
Views
9K
My Mistake? Understanding Friction Force & Work Done on Snowy & Icy Surfaces
Replies
29
Views
2K
Rotational ACC and Gravitational ACC
Replies
7
Views
2K
Work & Energy: Lifiting Water from a Well
Replies
22
Views
2K

Hot Threads

Recent Insights

Back
Top