Light Fundamentals (3) problems

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SUMMARY

The forum discussion centers on solving problems related to the speed of light and orbital mechanics. Participants calculate the distance light travels from the Moon to Earth, which is determined to be 3.84 x 108 meters, and the time it takes for sunlight to reach Earth, calculated as 0.5 seconds. Additionally, they explore the implications of Ole Romer's findings on light delay and Earth's orbital speed, ultimately arriving at a speed of approximately 3.56 x 1011 km/s. The discussion emphasizes the importance of unit conversion for accurate calculations.

PREREQUISITES
  • Understanding of basic physics concepts such as speed, distance, and time (d = vt).
  • Familiarity with light speed (approximately 3 x 108 m/s).
  • Knowledge of orbital mechanics and Kepler's laws.
  • Ability to perform unit conversions between meters, kilometers, and seconds.
NEXT STEPS
  • Research the implications of Ole Romer's measurements on the speed of light.
  • Learn about Kepler's Third Law and its applications in orbital mechanics.
  • Study unit conversion techniques for physics calculations.
  • Explore the relationship between luminous flux (lm) and illuminance (lx) in photometry.
USEFUL FOR

Students and educators in physics, astronomers, and anyone interested in understanding the principles of light speed and orbital dynamics.

whitehorsey
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1. Light takes 1.28 s to travel from the moon to Earth. What is the distance between them?

2. d= vt

3. d = vt
= 3 * 108(1.28)
= 3.84 * 108m


1.The sun is 1.5 * 108 km from Earth. How long does it take for its light to reach us?

2. d= vt

3. d = vt
t = d/v
= 1.5 * 108/ 3 * 108
= .5s
Did i do these 2 problems right? I'm not sure because it seems to easy.


b]1.Ole Romer found that the maximum increased delay in the appearance of lo from one orbit to the next was 14s.
a. How far does light travel in 14s?
b. Each orbit of lo is 42.5 h. Earth traveled the distance calculated above in 42.5h. Find the speed of Earth in km/s.
c. See if your answer for part b is reasonable. Calculate Earth's speed in orbit using the orbital radius, 1.5 * 108km, and the period, one year. [/b]

2. a/b. d= vt
c. ?


3. a) d = vt
= 3 * 108/14
= .4.2 * 109m

b) d= vt
v = d/t
= 4.2 * 109/42.5
= 98823529.41(3600)
= 3.56 * 1011km/s
c) I do not know if I should use Kepler's Third Law or d= vt to solve this problem.

I have a question for the equation E = P/4pid2. I know that the P represents the luminous flux, but can I put in m/s instead or does it work for lm only and what does lm and lx stand for? :confused:

Thank You! :smile:
 
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The first two are right ;-) They are as easy as they look.

For the third problem, part (a) you got right. Part (b) is mostly right but you need to be more careful with the units. If you're confused, one way to do it is to convert the distance to kilometers and the time to seconds before you divide. In part (c), why would you use Kepler's third law? It relates the orbital radius (a.k.a. semimajor axis) to the orbital period, but you already have both of those numbers. There's no need for you to calculate either of them.
 
The second problem is wrong. Don't forget your units.
 

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