Light Travel Time from Sun to Earth - HELP-HOMEWORK

AI Thread Summary
To calculate the time it takes for light to travel from the Sun to Earth, one must use the speed of light, which is approximately 186,282 miles per second, and the distance of 93 million miles. By applying the formula time = distance/velocity, the calculation reveals that light takes about 500 seconds, or roughly 8 minutes and 20 seconds, to make this journey. The analogy of driving 25 miles at 25 miles per hour helps clarify the concept of using speed and distance to find time. Understanding this relationship is crucial for solving the homework question. The discussion emphasizes the importance of applying basic physics principles to real-world scenarios.
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HELP-HOMEWORK...Hi, I have homework that ask "Using the velocity of light find an approximate value for the amount of time that it takes a light ray to travel from the sun to the earth." Now I know the distance between the Earth and the sun is 93 million miles but I'm not catching on to the question can anyone shed some light for me.(pun intended)
 
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Answer this question first: How long does it take you to drive 25 miles at 25 miles an hour? I bet you know that. Well, your question is the same. You got the velocity (182,000 miles a second -- instead of 25 miles an hour), you have the distance (93 million miles -- instead of 25 miles). Solve it.
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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