Lim(x*sqrt(1-cos(2*Pi/x)),x->Infinty) using analytical methods

  • Thread starter Thread starter dipstik
  • Start date Start date
  • Tags Tags
    Analytical
AI Thread Summary
The discussion revolves around finding the limit of the expression Lim(x*sqrt(1-cos(2*Pi/x)), x->Infinity) using analytical methods. The user initially derived the formulas for the circumference and area of a circle through polygons as the number of sides approaches infinity. They encountered difficulties with a 0 times infinity scenario and attempted multiple iterations of L'Hôpital's rule, leading to complex trigonometric functions. Suggestions include utilizing a double angle identity for cosine to simplify the expression under the square root. The focus remains on avoiding numerical methods and finding a clean analytical solution.
dipstik
Messages
127
Reaction score
4
Hey guys,

My cousin came over and was talking about his geometry class and it got me to derive 2*Pi*r and Pi*r^2 using polygons of n sides as n goes to infinity. For the area I ended up using a taylor expansion of sin to weasel myself out of a 0 times infinity, but this is not being very nice. I have tried three iteration of L'Hopital and ended up with a tangent, with more trig functions to come from further iterations I think. The limit converges nicely, pretty quickly too, but I don't want to use numerical methods. I tried a binomial expansion but ended up with a long list of 0*inf. terms there.

Any ideas?
 
Mathematics news on Phys.org
You have Cos(2*stuff) so use a double angle trig identity to get something squared in the sqrt.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Imaginary Pythagoras'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Back
Top