Proving the Limit of a Function Using Epsilon-Delta Definition

In summary, the given solution shows that for any given ε > 0, there exists a δ > 0 such that |x^2 - 4| < ε when 0 < |x - 2| < δ. This is proven by choosing a value of δ ≤ 1, which makes |x+2| < 3 and therefore |x^2 - 4| = |(x+2)(x-2)| = |x+2| ⋅ |x-2| < 3|x-2|. By choosing δ ≤ min{1, ε/3}, we can ensure that |x^2 - 4| < ε when 0 < |x - 2|
  • #1
azizlwl
1,066
10

Homework Statement


If f(x)=x2 prove that [tex] \lim_{x \to 2} f(x)= 4[/tex]
Solution given:
We must show that given any ε >0, find δ >0 such that |x2-4|<ε when 0<|x-2|<δ

Choose δ≤1 so that <|x-2|<1
-----------------------------------------------
Confuse between the word 'find' and 'choose'.
 
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  • #2


azizlwl said:

Homework Statement


If f(x)=x2 prove that [tex] \lim_{x \to 2} f(x)= 4[/tex]
Solution given:
We must show that given any ε >0, find δ >0 such that |x2-4|<ε when 0<|x-2|<δ

Choose δ≤1 so that <|x-2|<1
-----------------------------------------------
Confuse between the word 'find' and 'choose'.

##|x^2-4|=|(x+2)(x-2)|=|x+2|\cdot |x-2|##. So if ##|x-2|<1## how big can ##|x+2|## be? Then once you figure that out, how much smaller than 1 does ##|x-2|## need to be to make the whole thing less that ##\epsilon##?
 
  • #3


You can "find" many values of [itex]\delta[/itex] that will work and then "choose" one of those. That is the same as "finding" a value.
 
  • #4


Thanks. My confusion must be interpreting the word "find" as calculate in usual mathematics or physics problems.
 
Last edited:

1. How do you prove a limit?

To prove a limit, you must show that for any value of ε (epsilon) greater than 0, there exists a corresponding value of δ (delta) such that the distance between the input x and the limit L is less than ε whenever the distance between x and the point of interest a is less than δ.

2. What is the definition of a limit?

The definition of a limit is the value that a function approaches as its input approaches a certain point.

3. Can a limit exist even if the value of the function at the point does not exist?

Yes, a limit can exist even if the value of the function at the point does not exist. This is known as an "undefined" or "indeterminate" form, and it can occur when the function has a vertical asymptote or a removable discontinuity at the point of interest.

4. What are the properties of limits?

The properties of limits include the limit laws, which state that the limit of the sum, difference, product, or quotient of two functions is equal to the sum, difference, product, or quotient of their respective limits. Other properties include the Squeeze Theorem, which states that if two functions approach the same limit at a point, then any function squeezed between them must also approach that limit.

5. How do you use algebra to solve a limit?

To use algebra to solve a limit, you can try factoring, simplifying, or manipulating the function algebraically to get it into a form that can be evaluated directly. You can also use techniques such as L'Hôpital's rule or trigonometric identities to simplify the function and find the limit.

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